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Reds live series prices

Scheduled Pinned Locked Moved Diamond Dynasty
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  • Orcin_MLBTSO Offline
    Orcin_MLBTSO Offline
    Orcin_MLBTS
    wrote on last edited by
    #1

    Why are live series Reds cards more expensive than other NL Central teams?

    samguenther1987_PSNS 1 Reply Last reply
    0
  • samguenther1987_PSNS Offline
    samguenther1987_PSNS Offline
    samguenther1987_PSN
    replied to Guest on last edited by
    #2

    @Orcin_MLBTS said in Reds live series prices:

    Why are live series Reds cards more expensive than other NL Central teams?

    Because they have only 2 gold players and and even then they are only 80s, and 2 silver players. That makes them the choice to finish for most players so with everyone trying to finish them the price climbs on the their players.

    1 Reply Last reply
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  • bmoo44_PSNB Offline
    bmoo44_PSNB Offline
    bmoo44_PSN
    wrote on last edited by
    #3

    Gotta assume dibble

    1 Reply Last reply
    0
  • SaveFarris_PSNS Offline
    SaveFarris_PSNS Offline
    SaveFarris_PSN
    wrote on last edited by
    #4

    People really, really want Captain Dibble.

    1 Reply Last reply
    3
  • samguenther1987_PSNS Offline
    samguenther1987_PSNS Offline
    samguenther1987_PSN
    wrote on last edited by
    #5

    Or it could be because of Dibble lol

    1 Reply Last reply
    0
  • T Offline
    T Offline
    TheHungryHole_PSN
    wrote on last edited by
    #6

    100% because of dibble

    i got him today and you can scatter random reds pitchers to get his boost - i got the Tier 2 boost for dibbles this will carry me in RS and events for now - its one of the best team collections and this morning it cost me around 15K to do for the whole team

    1 Reply Last reply
    0
  • SuntLacrimae50_MLBTSS Offline
    SuntLacrimae50_MLBTSS Offline
    SuntLacrimae50_MLBTS
    wrote on last edited by
    #7

    Prices are always higher on non-diamonds for the bad teams. See also SF, OAK, CHIC, etc. Nothing to do with the rewards.

    1 Reply Last reply
    0

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